(-32/2500)x^2+x+220=100

Solution for (-32/2500)x^2+x+220=100 equation:

(-32/2500)x^2+x+220=100

We move all terms to the left:

(-32/2500)x^2+x+220-(100)=0


Domain of the equation: 2500)x^2!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

x+(-32/2500)x^2+120=0

We multiply all the terms by the denominator


x*2500)x^2+(+120*2500)x^2-32=0

We add all the numbers together, and all the variables

x*2500)x^2+300000x^2-32=0

Wy multiply elements

2500x^2=0

a = 2500; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·2500·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{5000}=0$